Posted in H2 Physics Answers

Suggested Answers to 2015 A Level H2 Physics 9646 Paper 3

H2 PHYSICS PRACTICAL

H2 CHEMISTRY PRACTICAL

H2 BIOLOGY PRACTICAL


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Suggested Answers to 2015 A Level H2 Physics 9646 Paper 3

1a) 1. Net external force acting on the system is zero

2. Net torque on the system about any point is zero

bi) Equilibrium system. Ball is falling at constant speed, resultant force is zero.

ii) Not equilibrium. There is resultant force in the form of centripetal force on the satellite due to the earth. There is a constant change in direction therefore there is change in velocity.

2a) 6.33 x 10^7  m

b)Bright fringes get dimmer, dark fringes get brighter.

c)For interference pattern to be seen, a should be much smaller than d. When this condition is not met, fringes cannot be seen. When a becomes too large, the central maximun diffraction bands will not be wide enough to produce inteference pattern.

3a) 14.0ºC

b) With an increase in temperature, the resistance of the thermistor drops. This leads to a drop in the circuit’s total resistance which increases the current through the thermistor, increasing the heating on the thermistor and further lowering the resistance. When the resistance is too low, the whole process will continue and result in a thermal runway, resulting in the thermistor permanently damaged by heat.

4a) Tesla is a unit of magnetic flux density when a uniform magnetic field normal to a wire carrying a current of 1A produces a force per unit length of 1N/m

bi) Force acting on the particle is always normal to the velocity of the particle.

ii) 2.38 x 10^-21 Ns

c) *Line is downwards with a smaller curvature.

5a) A photon is a packet of energy of electromagnetic radiation

bi) 3.84 x 10^-19  J

ii) 8.36 x 10^-25  Ns

c) 52.4º

6ai) Rate of change of velocity

ii) Since the radius of earth is 6400km, several km above the earth’s surface would not affect the acceleration of free fall.

bi) Surface area of the ball is too small or distance traveled by the ball is too short.

ii) 1. 0.299 s

2. 0.0362 s

c) 9.8%

di) The height to fall has now been decreased, thus it takes less time for the ball to travel to the point.

ii) The ball will be affected by the magnetic force exerted onto it, thus reducing the net downward force acting on the ball. As a result, the time taken will be longer.

e) Acceleration will decrease till it reaches zero. When air resistance is equal to the weight of the ball, the resultant force acting on the ball will be zero. Hence it has reached terminal velocity and acceleration is zero.

7ai) 1. 24.04 V

2. 60.5 Hz

ii) There is a heating effect regardless of direction of the current. It depends on the root mean square current instead of the average current. The heating effect is caused by power loss.

bi) The amount of thermal energy required to raise the temperature of 1 unit mass of the substance by 1ºC

ii) This indicates the power loss from the system to the surrounding.

iii) 4.22 x 10^3  J/kg K

c) *same gradient, y-intercept should be more negative.

di) The increase in internal energy of a system is equal to the sum of the thermal energy supplied to the system and the amount of work done on the system

ii)If specific heat capacity is measured at a constant volume, no work is done on system. If specific heat capacity is measured at constant pressure, there will be a change in volume. Hence, there is work done on the gas.

8ai) An object undergoing oscillatory motion with its acceleration directly proportional to its displacement from its equilibrium position. The acceleration is always towards the equilibrium position.

ii) 1. Acceleration is always opposite in direction of displacement. Hence it is oscillating.

2. Acceleration is not directly proportional to its displacement. Hence, oscillations are not simple harmonic.

bi) 1. A wave in which the particles oscillates parallel to the direction of propagation.

2. The speed of the wave means the distance traveled per unit time by a wave front.

ii) 1. 1.20 x 10^-3

2. 1.20 x 10^-3

3. 3.20 x 10^-3  m/s

4. 2.71 x 10^-31  J

iii) Sound waves moves relatively fast in gas but the gas molecules oscillate back and forth about their original positions with relatively small speeds.

ci) Energy of the wave originates from the vibrational motion of the gas molecules.

ii) It is caused by the pressure imbalance from the disturbance of the gas’ uniform density.

 

 

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A-LEVEL H2 PHYSICS JUNE HOLIDAYS INTENSIVE REVISION

 

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Posted in H2 Physics Answers

Suggested Answers to 2015 A Level H2 Physics 9646 PAPER 1 and 2

H2 PHYSICS PRACTICAL

 

H2 CHEMISTRY PRACTICAL

 

H2 BIOLOGY PRACTICAL

 


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Physics Paper 1 MCQ

1) A  2) D  3) C  4) A  5) C

6) A  7) D  8) C  9) A  10) C

11) B  12) A  13) D  14) A  15) A

16) A  17) C  18) A  19) C  20) B

21) C  22) D  23) B  24) B  25) A

26) B  27) B  28) B  29) D  30) B

31) B  32) D  33) B  34) C  35) C

36) C  37) C  38) A  39) D  40) B

 

Physics Paper 2

1. a) EPE = 0.662J

bi) The system has only GPE before the 300g mass is released. After releasing, part of the GPE is converted to KE and to EPE. At the lowest point, once the mass comes to a stop, all of the GPE will have been converted to EPE.

ii) v = 1.21 m/s

iii) 0.40m

2a) Select 2 points from the graph: (6.0, 1.25) and (12.0, 2.50)

(V – 12.0)/(I – 2.50) = (12.0 – 6.0) / (2.50 – 1.25)

V – 12.0 = (6.0/1.25) (I – 2.50)

V = 4.81I

V is proportional to I

bi) 4.8Ω

ii) 1.3 A ,  1.6A

iii) 6.35 V

3a) Incident photons must have energy greater than or equal to the work function of M to emit one electron. Energy of photon is related to the frequency of the electromagnetic radiation by E = hf

bi) Free electrons at the surface are emitted with maximum KE but electrons of the outer shell require more energy to escape thus they will be emitted with less KE. A minimum potential difference is present to stop the photoelectrons with the maximum KE from reaching the collector in order to reduce the current to zero.

ii)It is limited by rate of emission of photoelectrons, which is dependent on the intensity.

c) 9.45 x 10^14  Hz

d) Starts from -2.2v and follows the same shape of the original. The value of y-intercept is doubled due to the doubled intensity.

4a) 0.712 m/s^2

bi) Since the 2 moons move in circular orbits around Jupiter’s center of mass, thus the centripetal force is also the gravitational force due to Jupiter, which acts towards Jupiter’s center of mass.

ii) 2.33

5ai) 4.80 x 10^-14 N

ii) -2.30 x 10^-16 N

b) Electrostatic force on A due to B and B due to A are internal forces. They have the same magnitude but different in direction. Thus the resultant force action on the molecule is zero.

c) 1.6628 x 10^-25  Nm

6a) 128, 54

b) 1510 s

7ai) s = -3.0

ii) -3.170 , -0.693

iii) Plot the point and draw the best fit line.

iv) 3.10

v) There is a linear relationship between ln(y1/m) and ln(l/m) with a gradient of 3.1 and with a y- intercept of -1.02.

vi) 3

b) k = 2.70 x 10^-10

ci) Acceleration is directly proportional to the displacement. The negative sign indicates that the acceleration is opposite to the displacement and is always directed to the position of zero displacement.

ii) 0.560

8.

Apparatus.

Filament lamp, power supply, beaker, thermometer, Stirrer, Stopwatch, Voltmeter, Ammeter, Rheostat, Switch, Weighing machine, Waterproof tape.

Draw a diagram with a filament lamp immersed in water, with the thermometer and stirrer inside the beaker. Draw the circuit of the lamp with connecting ammeter and voltmeter and the power source.

Procedure.

1. Measure mass of water in beaker, m.

2. Insulate the beaker.

3. Connect filament lamp with circuit, wrap the metal cap with the waterproof tape.

4. Set up apparatus as shown.

5. Record initial temperature.

6. Close the circuit and start the stopwatch.

7. When the temperature hits 70ºC, stop the stopwatch and record the readings of the voltmeter and ammeter.

8. Repeat steps 5 to 7 after replacing the hot water in the beaker with the same amount of water at room temperature. Obtain different potential differences by changing the resistance of the rheostat.

Working

1. 1 – (Thermal energy/electrical energy output)

2. Relationship between I and t is given by η = aV^b , where a and b are constants. The equation can be written as lg η  = b lg V + lg a

3. Plot a graph of lg η against lg V and obtain a and b

Accuracy

1. Minimise heat loss to surroundings by using the lid and lagging.

2. Conduct preliminary experiments to decide on the suitable values of resistance and voltage supply.

3. Ensure experiment is not conducted over long periods of time so that efficiency of the lamp is not affected by the thermal energy released.

Safety

1. Handle with dry hands to prevent electrocution.

2. Ensure the circuit is not in contact with the water.

3. Handle the beaker with care when replacing the water.

 

 

 

A-LEVEL H2 MATH JUNE HOLIDAYS INTENSIVE REVISION

A-LEVEL H2 PHYSICS JUNE HOLIDAYS INTENSIVE REVISION

 

JUNIOR COLLEGE / A-LEVEL TUITION:

 

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Posted in H2 Math Answers

Suggested Answers to 2015 A Level H2 Math 9740 PAPER 2

 

1. Differential equation

(i) h = 32m

(ii) ≈ 46.9 years

 

2. Vectors

(i) ≈ 73.4°

(ii) λ = 3/7 or 1

Point = ( 17/7 , 1/7 , -58/7 )

(iii) -36x + 2y – 11z = 4

 

3. Functions

a)(i) Graph of y=k , k∈R , cuts at most on 1 point.

f (x) is a 1 – 1 function, f inverse exists

(ii) f -¹ : x → √(1 – 1/x) , x > 0

b) y≤ 1 – (1/2)√3  or  y≥ 1 + (1/2)√3

Rg = ( -∞, 1 – (1/2)√3] ∪ [ 1 + (1/2)√3 , ∞ )

 

4. Mathematical induction / Method of difference

b)(i) 2 = A(2r+3) + B(2r+1)

(ii) (1/3) – (1/(2n+3))

(iii) n≥ 1498.5

smallest n = 1499

 

5. Sampling methods

(i)  Sampling frame is not available, therefore the manager is unable to define the appropriate subgroups required for stratified sampling.

(ii)  Survey 25 people each for different age groups  (5-20, 21-40, 41-60, 61-80). The manager can survey the customers going in and out of the supermarket to obtain the  required data.

6. Binomial distribution

(i) ≈ 0224

(ii) ≈ 0.149

(iii) ≈ 0.825

 

7. Poisson distribution

(i) Average number of errors per page is constant

Errors occurring are independent of each other

(ii) ≈ 0.165

(iii) least n = 4

 

8. Hypothesis Testing

p-value = 0.264618 > 0.1

Do not reject Ho. There is insufficient evidence at the 10% level of significance to doubt his claim.

 

9. Probability

(i) = 0.4

(ii) 0.185

(iii) Lowest = 0.165

Highest = 0.33

 

10. Correlation and Regression 

i)

qcc

(ii) a. ≈ -0.9807

b. ≈ -0.9748

c. ≈ -0.9986

(iii) √h and P

P = 34.8 – 0.266√h

(iv) 34.8 – 0.266√h

 

11. Permutations and Combinations

(i) 10080

(ii) 10079

(iii) 720

(iv) 5760

 

12. Normal Distribution

(i) 0.01267

(ii) 0.05238

(iii) 0.742

 

 

 

 

A-LEVEL H2 MATH JUNE HOLIDAYS INTENSIVE REVISION

A-LEVEL H2 PHYSICS JUNE HOLIDAYS INTENSIVE REVISION

 

JUNIOR COLLEGE / A-LEVEL TUITION:

 

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physics jc               chem jc

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f math                econs

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Posted in H2 Math Answers

Suggested Answers to 2015 A Level H2 Math 9740 PAPER 1

 

1. System of linear equations / Graphing techniques

(i)  a = -3.953 ,  b = -5.187 ,  c = 7.303

(ii)  x = -0.589

(iii)  y = 5.19x + 7.3

 

2. Graphing techniques / Inequalities

i)

q2

(ii) -1.73 < x < 0.414  or  x > 1.73

 

3. Integration

(i) When n→∞ , sum of area of rectangles ≈ area of function

(ii) 3/4

 

4. Application of differentiation

Maximum area = (1/32) d²

 

5. Graphing techniques / Transformation

(i) Translation of +3 units parallel to the x-axis,

Scaling by scale factor of 1/4 parallel to the y-axis

ii)

iii)

 

 

6. Maclaurin’s series / Binomial expansion

(i) 2x – 2x² + (8x³/3)

(ii) -(104/27)

 

7. Vectors

(i) OC = (3/5)a

OD = (5/11)b

(ii) line BC : r = (3/5)λa + (1 – λ)b

line  AD : r = (1 – μ)+ (5/11)μb

(iii) AE : ED = 11:9

 

8. AP/GP

(i) T = { T∈R : 59 ≤ T ≤ 77 }

(ii) t = { t∈R : 63.8 ≤ t ≤ 74.5 }

9. Complex numbers

a) w = a ± (a/√3)i

b)(i) z = 2e^(-π/10) , 2e^(3π/10) , 2e^(-π/2) , 2e^(7π/10) , 2e^(-9π/10)

(ii) 4 sin ( π/5)

10. Application of integration

i) A1/A2 = (2-√2)/(√2 -1)

= √2

iii) Volume = (π³/16√2) + (π²/2√2) – √2 π

11. Application of differentiation and integration

i) dy/dx = (-3sin³Θ + 6sinΘ cos²Θ)/(3sin²Θ cosΘ)

= 2 cot Θ – tan Θ (shown)

ii) ( (2√2)/(3√3) , ( 2 /√3 ) ) maximum point

iii) Area ≈ 0.884

iv) a = (3√2)/(2)

 

A-LEVEL H2 MATH JUNE HOLIDAYS INTENSIVE REVISION

A-LEVEL H2 PHYSICS JUNE HOLIDAYS INTENSIVE REVISION

 

JUNIOR COLLEGE / A-LEVEL TUITION:

 

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physics jc               chem jc

poa                mob

f math                econs

_______________________________________________________________________

TUITION FEES

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Posted in School Rankings, Schools

List of Junior Colleges (JC) (2015) in Singapore by Cut-Off L1R5 aggregate score (including bonus points)

Wishing you all the best for your O-Level results.

The following links may be relevant to you:

Between JC and Poly …

Which one to choose? The IB or the A-levels?

Which subject combination to choose in JC?

SCIENCE PRACTICAL TRAINING

H2 PHYSICS PRACTICAL

H2 CHEMISTRY PRACTICAL

H2 BIOLOGY PRACTICAL

 

 

 

 


Below is the latest ranking of JCs that I have compiled based on their 2015 cut-off points. As expected, RI and HCI have remained at the top. Compared to 2014, NJC is now in the same position as VJC, NYJC has outranked even TJC, and PJC occupies the same position as TPJC. In terms of COP, it seems that over the last few years NYJC and PJC have been improving while TJC has been going south. Please note that this list is based on cut-off points, not A-Level results. DHS and RVHS are not in the list as they do not take in O-Level leavers.

LATEST! List of Junior Colleges by Cut-Off L1R5 aggregate (2018) score (with bonus points)

S/No Junior College Arts Science/IB
1 Hwa Chong Institution 4 3
2 Raffles Institution 4 3
3 National JC 6 5
4 Victoria JC 6 5
5 Anglo-Chinese School   (Independent) 5
6 Anglo-Chinese JC 7 6
7 St. Joseph’s   Institution 6
8 Nanyang JC 7 7
9 Temasek JC 8 8
10 Anderson JC 9 8
11 St. Andrew’s JC 9 9
12 Meridian JC 9 10
13 Catholic JC 10 10
14 Serangoon JC 11 11
15 Tampines JC 13 13
16 Pioneer JC 13 13
17 Jurong JC 15 15
18 Yishun JC 16 17
19 Innova JC 18 20

SCIENCE PRACTICAL TRAINING

H2 PHYSICS PRACTICAL

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H2 BIOLOGY PRACTICAL

 

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Posted in Schools

List of ‘Top’ Secondary Schools (2015) in Singapore by Cut-Off PSLE aggregate score (2014)

Here is the list of the ‘top’ 37 secondary schools by COP for 2015. I have chosen to cut the list off at the COP of 235. If a school has both IP and non-IP streams, the COP listed is only for IP. If a school has both Affiliation and Non-Affiliation groups, the COP listed is only for the Non-Affiliation group.

Name of School COP 2015 Highest Score Median
NANYANG GIRLS’ HIGH SCHOOL 262 277 265
RAFFLES GIRLS’ SCHOOL (SECONDARY) 258 273 262
RAFFLES INSTITUTION 256 275 261
HWA CHONG INSTITUTION 256 270 259
METHODIST GIRLS’ SCHOOL (SECONDARY) 256 268 258
NATIONAL JUNIOR COLLEGE 254 268 256
DUNMAN HIGH SCHOOL 253 269 257
CHIJ ST. NICHOLAS GIRLS’ SCHOOL 253 269 256
CEDAR GIRLS’ SECONDARY SCHOOL 252 267 255
ANGLO-CHINESE SCHOOL (INDEPENDENT) 252 265 254
SINGAPORE CHINESE GIRLS’ SCHOOL 250 265 252
TEMASEK JUNIOR COLLEGE 249 264 252
RIVER VALLEY HIGH SCHOOL 249 269 253
CATHOLIC HIGH SCHOOL 249 262 253
VICTORIA SCHOOL 249 267 252
ST. JOSEPH’S INSTITUTION 248 265 251
ANDERSON SECONDARY SCHOOL 245 263 247
BUKIT PANJANG GOVT. HIGH SCHOOL 245 264 248
CHIJ SECONDARY (TOA PAYOH) 243 249 245
NAN HUA HIGH SCHOOL 242 260 246
CRESCENT GIRLS’ SCHOOL 242 257 245
ST. MARGARET’S SECONDARY SCHOOL 242 247 243
ST. ANDREW’S SECONDARY SCHOOL 242 245 242
FAIRFIELD METHODIST SCHOOL (SECONDARY) 241 253 242
PAYA LEBAR METHODIST GIRLS’ SCHOOL 241 253 243
NAN CHIAU HIGH SCHOOL 240 265 245
ANGLICAN HIGH SCHOOL 239 271 245
SWISS COTTAGE SECONDARY SCHOOL 239 259 241
CHUNG CHENG HIGH SCHOOL (MAIN) 238 257 242
COMMONWEALTH SECONDARY SCHOOL 237 268 239
NGEE ANN SECONDARY 236 256 240
CHUNG CHENG HIGH SCHOOL (YISHUN) 236 255 239
YISHUN TOWN SECONDARY SCHOOL 236 263 240
TANJONG KATONG GIRLS’ SCHOOL 235 258 239
MARIS STELLA HIGH SCHOOL 235 257 238
XINMIN SECONDARY SCHOOL 235 251 238

Related Links:

O-LEVEL PHYSICS PRACTICAL

O-LEVEL CHEMISTRY PRACTICAL

O-LEVEL BIOLOGY PRACTICAL


O-LEVEL SCIENCE (PHYSICS) PRACTICAL

O-LEVEL SCIENCE (CHEMISTRY) PRACTICAL

O-LEVEL SCIENCE (BIOLOGY) PRACTICAL

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Posted in A. Math

Was A. Math Paper 1 (2015) difficult?

Yes, according to some students. Some said it was “harder than expected”. One couldn’t do Q4 properly and another gave up on Q6. These are some of the chatter that reached me. Well, if you think you had done badly in P1, then please be more careful tomorrow. And DO NOT PRACTISE ANY A.MATH TONIGHT.

Anyway, even if you didn’t too well in A. Math, you still can get A for math in JC, provided you start early. So if you intend to go to JC and take up Math (H2 or H1), and your sec math is always around A2-B4, then I would encourage you to attend our JC Math Headstart or Bridging classes this Nov or Dec. Please remember that IP students have already learnt some JC Math in Sec 4, so you’d have some catching up to do even if you had done well in any O-Level Math.

Our JC1 H2 Math Headstart classes will commence on Sun 15 Nov or Sat 21 Nov. You can find more details here: Our JC & Secondary Headstart Programmes 2015-2016. “Early bird” sign-ups will of course be given discounts. You can also sms your queries to 97860411. Thank you.

ALL THE BEST FOR TOMORROW!

Posted in A. Math, Personal

Heard O-Level (2015) Math Paper 2 was “easy”.

I smsed a few tutees about Math Paper 2, and the responses were:

  • “easier than paper 1”
  • “much better than p1 yay”
  • “got all correct except Q7b”
  • “finished in 1.5 hrs”

Okayyy, I get the message.  So all of you are going to get A1 for p2 but when combined with p1 you are going to get A2? Just joking. What is more certain is that since p2 is easy, the examiners will “find fault” with your answers in any way they can – presentation, d.p., sig fig, labelling on graphs, units, reasons for trigo etc.

Anyway, pls focus on A. Math tmr. Get some sleep.

Rgds,

Ilyasa

Posted in Exam Answers

Suggested answers to GCE O Level 2015 A. Math (4047) Paper 1

I’m just getting ready. Please paste your suggested answers here when the time comes and let others comment on it.  Thank you.

Related links:

O-LEVEL 2015 PHYSICS MCQ INTENSIVE DRILL SESSION (500+ MCQs)

Our JC & Secondary Headstart Programmes 2015-2016 [NOTE:  Our JC1 (2016) HEADTSTART & BRIDGING classes for General Paper, Economics, Math, Physics & Chemistry start from 15 Nov 2015 onwards. REGISTER NOW to avoid disappointment]