Posted in H2 Physics Answers

Suggested Answers to 2015 A Level H2 Physics 9646 PAPER 1 and 2

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Physics Paper 1 MCQ

1) A  2) D  3) C  4) A  5) C

6) A  7) D  8) C  9) A  10) C

11) B  12) A  13) D  14) A  15) A

16) A  17) C  18) A  19) C  20) B

21) C  22) D  23) B  24) B  25) A

26) B  27) B  28) B  29) D  30) B

31) B  32) D  33) B  34) C  35) C

36) C  37) C  38) A  39) D  40) B

 

Physics Paper 2

1. a) EPE = 0.662J

bi) The system has only GPE before the 300g mass is released. After releasing, part of the GPE is converted to KE and to EPE. At the lowest point, once the mass comes to a stop, all of the GPE will have been converted to EPE.

ii) v = 1.21 m/s

iii) 0.40m

2a) Select 2 points from the graph: (6.0, 1.25) and (12.0, 2.50)

(V – 12.0)/(I – 2.50) = (12.0 – 6.0) / (2.50 – 1.25)

V – 12.0 = (6.0/1.25) (I – 2.50)

V = 4.81I

V is proportional to I

bi) 4.8Ω

ii) 1.3 A ,  1.6A

iii) 6.35 V

3a) Incident photons must have energy greater than or equal to the work function of M to emit one electron. Energy of photon is related to the frequency of the electromagnetic radiation by E = hf

bi) Free electrons at the surface are emitted with maximum KE but electrons of the outer shell require more energy to escape thus they will be emitted with less KE. A minimum potential difference is present to stop the photoelectrons with the maximum KE from reaching the collector in order to reduce the current to zero.

ii)It is limited by rate of emission of photoelectrons, which is dependent on the intensity.

c) 9.45 x 10^14  Hz

d) Starts from -2.2v and follows the same shape of the original. The value of y-intercept is doubled due to the doubled intensity.

4a) 0.712 m/s^2

bi) Since the 2 moons move in circular orbits around Jupiter’s center of mass, thus the centripetal force is also the gravitational force due to Jupiter, which acts towards Jupiter’s center of mass.

ii) 2.33

5ai) 4.80 x 10^-14 N

ii) -2.30 x 10^-16 N

b) Electrostatic force on A due to B and B due to A are internal forces. They have the same magnitude but different in direction. Thus the resultant force action on the molecule is zero.

c) 1.6628 x 10^-25  Nm

6a) 128, 54

b) 1510 s

7ai) s = -3.0

ii) -3.170 , -0.693

iii) Plot the point and draw the best fit line.

iv) 3.10

v) There is a linear relationship between ln(y1/m) and ln(l/m) with a gradient of 3.1 and with a y- intercept of -1.02.

vi) 3

b) k = 2.70 x 10^-10

ci) Acceleration is directly proportional to the displacement. The negative sign indicates that the acceleration is opposite to the displacement and is always directed to the position of zero displacement.

ii) 0.560

8.

Apparatus.

Filament lamp, power supply, beaker, thermometer, Stirrer, Stopwatch, Voltmeter, Ammeter, Rheostat, Switch, Weighing machine, Waterproof tape.

Draw a diagram with a filament lamp immersed in water, with the thermometer and stirrer inside the beaker. Draw the circuit of the lamp with connecting ammeter and voltmeter and the power source.

Procedure.

  1. Measure mass of water in beaker, m.

  2. Insulate the beaker.

  3. Connect filament lamp with circuit, wrap the metal cap with the waterproof tape.

  4. Set up apparatus as shown.

  5. Record initial temperature.

  6. Close the circuit and start the stopwatch.

  7. When the temperature hits 70ºC, stop the stopwatch and record the readings of the voltmeter and ammeter.

  8. Repeat steps 5 to 7 after replacing the hot water in the beaker with the same amount of water at room temperature. Obtain different potential differences by changing the resistance of the rheostat.

Working

  1. 1 – (Thermal energy/electrical energy output)

  2. Relationship between I and t is given by η = aV^b , where a and b are constants. The equation can be written as lg η  = b lg V + lg a

  3. Plot a graph of lg η against lg V and obtain a and b

Accuracy

  1. Minimise heat loss to surroundings by using the lid and lagging.

  2. Conduct preliminary experiments to decide on the suitable values of resistance and voltage supply.

  3. Ensure experiment is not conducted over long periods of time so that efficiency of the lamp is not affected by the thermal energy released.

Safety

  1. Handle with dry hands to prevent electrocution.

  2. Ensure the circuit is not in contact with the water.

  3. Handle the beaker with care when replacing the water.

 

 

 

A-LEVEL H2 MATH JUNE HOLIDAYS INTENSIVE REVISION

A-LEVEL H2 PHYSICS JUNE HOLIDAYS INTENSIVE REVISION

 

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Posted in H2 Math Answers

Suggested Answers to 2015 A Level H2 Math 9740 PAPER 1

 

1. System of linear equations / Graphing techniques

(i)  a = -3.953 ,  b = -5.187 ,  c = 7.303

(ii)  x = -0.589

(iii)  y = 5.19x + 7.3

 

2. Graphing techniques / Inequalities

i)

q2

(ii) -1.73 < x < 0.414  or  x > 1.73

 

3. Integration

(i) When n→∞ , sum of area of rectangles ≈ area of function

(ii) 3/4

 

4. Application of differentiation

Maximum area = (1/32) d²

 

5. Graphing techniques / Transformation

(i) Translation of +3 units parallel to the x-axis,

Scaling by scale factor of 1/4 parallel to the y-axis

ii)

iii)

 

 

6. Maclaurin’s series / Binomial expansion

(i) 2x – 2x² + (8x³/3)

(ii) -(104/27)

 

7. Vectors

(i) OC = (3/5)a

OD = (5/11)b

(ii) line BC : r = (3/5)λa + (1 – λ)b

line  AD : r = (1 – μ)+ (5/11)μb

(iii) AE : ED = 11:9

 

8. AP/GP

(i) T = { T∈R : 59 ≤ T ≤ 77 }

(ii) t = { t∈R : 63.8 ≤ t ≤ 74.5 }

9. Complex numbers

a) w = a ± (a/√3)i

b)(i) z = 2e^(-π/10) , 2e^(3π/10) , 2e^(-π/2) , 2e^(7π/10) , 2e^(-9π/10)

(ii) 4 sin ( π/5)

10. Application of integration

i) A1/A2 = (2-√2)/(√2 -1)

= √2

iii) Volume = (π³/16√2) + (π²/2√2) – √2 π

11. Application of differentiation and integration

i) dy/dx = (-3sin³Θ + 6sinΘ cos²Θ)/(3sin²Θ cosΘ)

= 2 cot Θ – tan Θ (shown)

ii) ( (2√2)/(3√3) , ( 2 /√3 ) ) maximum point

iii) Area ≈ 0.884

iv) a = (3√2)/(2)

 

A-LEVEL H2 MATH JUNE HOLIDAYS INTENSIVE REVISION

A-LEVEL H2 PHYSICS JUNE HOLIDAYS INTENSIVE REVISION

 

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Posted in A. Math

Was A. Math Paper 1 (2015) difficult?

Yes, according to some students. Some said it was “harder than expected”. One couldn’t do Q4 properly and another gave up on Q6. These are some of the chatter that reached me. Well, if you think you had done badly in P1, then please be more careful tomorrow. And DO NOT PRACTISE ANY A.MATH TONIGHT.

Anyway, even if you didn’t too well in A. Math, you still can get A for math in JC, provided you start early. So if you intend to go to JC and take up Math (H2 or H1), and your sec math is always around A2-B4, then I would encourage you to attend our JC Math Headstart or Bridging classes this Nov or Dec. Please remember that IP students have already learnt some JC Math in Sec 4, so you’d have some catching up to do even if you had done well in any O-Level Math.

Our JC1 H2 Math Headstart classes will commence on Sun 15 Nov or Sat 21 Nov. You can find more details here: Our JC & Secondary Headstart Programmes 2015-2016. “Early bird” sign-ups will of course be given discounts. You can also sms your queries to 97860411. Thank you.

ALL THE BEST FOR TOMORROW!

Posted in O-Level Math

Suggested answers to GCE O Level 2015 Math (4016) Paper 1 (via crowdanswering)

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Ok. Some people have sent me some answers. Here they are. Good luck.

1.  -30

2.  $966

3.  4,4,5,10,12

  1. 119

5.  (61x – 18) / 12

  1. (a) {4, 8}       (b)  shade outside the two ovals

7.  (4x-3y)(a-2b)

8.(a)  B(2,-2)     (b)  6.71 units

9.  Mean = 162 g;  SD = 5.48 g

  1. $32680

  2. 45 deg, 27 deg, 108 deg

12 (ai) 1.5 L   (ii) 4.5 L    (b)  6:15:20

13.   5 hrs  52 min

14.  (a)  2 x 3^2 x 5^2    (b)    90,  75

15.  (a)  3 < x <= 8.5      (b)   4, 5, 6, 7 , 8

16.  216 deg

17 (a)  28.6 cm    (b)   1.37

18.  141.9 deg

19.  716 cm squared

20 (a)  (shown) [whatever that means]   (b)  (16, -5)   (c)  160 sqr units

21 (a)  q = (A-2(pi)p^2) / (pi)p   (b)  3r

22(a)  P=(1st row 4  2  3; 2nd row 3  0  4)    (b)  R = (1st row  15   -0.3;  2nd row  10.1   0.2)

22(c)   $0.20    (d)   $13.23

23 (a) I don’t have to show you   (b)  3(pi)r2

24(a)  (10-n)/10   (b)  (90-19n+n^2)/90

24(c)(I)  show it yourself   (ii)  3

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Posted in O-Level Math

Heard O-Level (2015) Math paper 1 was “hard” or “unusual”.

A tutee from Crescent Girls’ said it was “harder than in past years”.  And already there is someone who found my website today using the search phrase “am i eligible for jc when fail o level maths”.

My daughter said it was “tedious” and had “ugly” numbers. But she admitted it was easier than her prelims. Anyway, please remember that Paper 2 isn’t over yet. Even if you had lost today’s battle, you have not lost the war against Math.

Anyway, all the best to you if you are doing O-levels this year!

Rgds,

Ilyasa

Our JC & Secondary Headstart Programmes 2015-2016

Posted in Exam Answers, Pure Chemistry

Suggested answers to GCE O Level 2014 Chemistry (5073) Paper 1

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Here are the suggested answers for O Level Chemistry Paper 1, worked out by our O-Level Chemistry Tutor Mr Eric Lee (Mr Lee is also our H2 Chemistry tutor). Detailed explanations will be posted soon. Answers for paper 2 will be posted soon too.

  1. B
  2. A
    3. A (corrected)
  3. B
  4. A
  5. A
  6. C
  7. D
  8. D
  9. B
  10. C
  11. D
  12. B
  13. A
  14. D
  15. A
    17. B
  16. C
  17. C
  18. C
  19. C
  20. D
  21. C
  22. D
  23. C
  24. A
  25. B
  26. C
  27. A
  28. C
  29. B
  30. B
  31. B
  32. B
  33. D
  34. B
  35. C
  36. B
  37. D
  38. D

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scan scan0014 scan0015 scan0016scan0017 scan0018

 

Posted in Pure Chemistry

Some words of advice for O level Chemistry MCQ (Paper 1)

Tips to look out for O level Chemistry MCQ:

– Remember: you only have 1 hr to complete 40 questions, that is a maximum of 1 hr 30 sec for each question with zero time for checking at the end of the examination.

– My advice is to spend 1 minute for each question so that you can some extra time to come back and think about the questions you skipped and also do a quick check of your answers (e.g. whether you shade your answers correctly or not).

– Don’t spend too long on ONE question. If you don’t know, just skip first. Don’t waste time on ONE question you don’t know and rush through the last 10 questions towards the end when time is running out. The last 10 questions may be the easy questions to be answered!

– Shade your answers IMMEDIATELY. You can circle the answers on the question book but DO NOT leave it to the last minute to transfer your answers. If you have limited time towards the end, you will rush through the shading and most likely you will shade wrongly. You just need to miss one question for the whole shading process to turn into a disaster.

– Do your calculation questions fast and accurate, take note of careless mistakes.

– Remember the solubility rules at your fingertips and your Qualitative Analysis.

– Read the four options given to you. Do not rush into selecting the option you THINK is correct. Remember to always choose the BEST answer from the four options. Sometimes, 2 options may seem correct at first glance but you are to choose the BEST answer. You need to convince yourself that the other 3 options are WRONG. And you have to do this within the time limit.

– Be confident of your concepts. Study hard and you will excel in your Paper 1.

Good luck and all the best!

Mr Lee

(Mr Lee is Singapore Learner’s Chemistry Tutor)

Posted in A-Level, JC Math (H2/H1)

Suggested Answers to 2014 A Level H2 Math 9740 Paper 1

MOCK EXAMS FOR SCIENCE PRACTICAL


The following is a suggested solution by our H2 and H1 Math Tutor, Mr. Teng. Please note that it is a suggested solutions and was rushed out. Mr. Teng omitted several presentation steps out of convenience. There might be alternative solutions at times too. Feel free to comment and discuss. We will try our best to answer.

Errata:

Qn3 I misread it. Answer should be 2/3 and need not be evaluated.

Qn5i I copied wrongly off GC. answer should -3+4i.  It shouldn’t affect the back parts.

Qn7 I copied wrongly off GC. So rounding off, the answers should α=1.885(3dp)

 

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Advice and tips from Mr Teng for H2 Math exam 2014 paper 2

Please focus on tomorrow’s paper 2 and not let paper 1 affect you too much.

Errata:

Qn3 I misread it. Answer should be 2/3 and need not be evaluated.

Qn5i I copied wrongly off GC. answer should -3+4i.  It shouldn’t affect the back parts.

Qn7 I copied wrongly off GC. So rounding off, the answers should α=1.885(3dp)

Much thanks for those that point it out.

 

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Posted in A. Math

Suggested answers to GCE O Level 2014 A. Math (4047) Paper 1

1.  k = -2

2.  sqrt(26)/26

3.  1.75

4.  -3/x   –  2/x^2  +  4/(x-2)

5(i) v = 0.263

5(ii) around v = 0.231

5(iii) around f = 0.120

6. (i) Remember that when there is a mixture of trigo functions which cannot fit into a single trigo identity, convert all the given trigo functions into sine and cosine. Start with the LHS, the more complicated expression.  You will reach the key stage where

LHS = 1 / [(1 – sin^2@)/(sin@cos@)] = 1/ (cos^2@/sin@cos@) = 1/(cos@/sin@) = tan@

6(ii) acute angle, so @ = 1.05.

7(i) A = (h, 2h);  B = (7h/4, 2h);  C = (h, h/2)

7(ii) Area of trapezium = 21 sqr units.

8. Integrate f'(x) to get f(x) with a +c. Use f(pi/2) = 0 to get c = 1/4. Differentiate f'(x) to get f”(x)= 4cos4x + 2sin2x. Proceed to add f”(x) to 4f(x) to get the RHS.

9(i) Pure inequality question. Solve 2x^2 + 5x – 12 > 0 by sketching a quadratic graph. Ans:  {x :  x < -4  U  x > 3/2}

9(ii) Show that the (b^2 – 4ac) of (4x^2 + 4x + 1 = 0) is zero.

9(iii) a = -1.

 

To be continued ….

Posted in O Level

Suggested answers to GCE O Level 2014 Math (4016) Paper 1 (via crowdanswering)

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PRACTICAL CRASH COURSES

 


1) sqrt (0.48), 0.702, 27/38, 0.61

2) 3.90 swiss francs

3a) 629.25

3b) 630

4) 47.9 deg or 132.1 deg (or 0.836 rad or 2.31 rad)

5) zero hours not offered; the choices given for the intervals for the number of hours spent are not continuous; time limit, such as per day or per week, not set.

6) – 1/3 (corrected)

7) 112

8) 79.4%

9a) 1000

9b) 200%

10a) 32 sec

10b) 7.5 sec

11) $78.50

12) x = 3 cm, y = 5 cm, z = 15 cm

13) $7500

14a) 1/3 (b a)

14b) vector DC cannot be expressed as k(vector OA), so vectors DC and OA are not parallel.

15a) Two circles overlapping

15b) {4,6,7,8,9,10,11}

16a) 3b^5/2a

16b) (8x-5)/(x-3)^2

17a) a = 5, b = 19, c = 26

17b) 7n – 2

c) There is no integer value of n such that 7n-2 = 109

18a) 8  11/18 m/s

18b) 9 min 43 sec

19a) graph curves upwards, passes thru origin

19b) s = 2.25 t^2

19c) 2.98 sec

20a) 1/4

20b) 1/16

20c) 55/64

21ai) (2.6 4.3 6.8) as in 3×1 matrix

21aii) E = (151.4 135.4) as in 2×1 matrix

21aiii) It represents the masses of the coins saved by Lin and Hadi respectively

21b) (10 20 100) as in 3×1 matrix

22) $644.17

23a) 314 cm^2

23b) 5 cm by 7 cm by 11 cm

23c) 42

24a) 9(x-1)

24b) 57 cm

24c) 196 cm^2

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Suggested answers to GCE O Level 2014 Math (4016) Paper 2

 

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